Base | Representation |
---|---|
bin | 110001111110010010000… |
… | …111001001001010000011 |
3 | 110011022002102212020102112 |
4 | 301332102013021022003 |
5 | 422231044313344210 |
6 | 11145341224405535 |
7 | 503051643126524 |
oct | 61762207111203 |
9 | 13138072766375 |
10 | 3434130215555 |
11 | 1104451a85196 |
12 | 4756833168ab |
13 | 1bbab6117660 |
14 | bc2d9c7284b |
15 | 5e4e265dd05 |
hex | 31f921c9283 |
3434130215555 has 128 divisors (see below), whose sum is σ = 4778839296000. Its totient is φ = 2350521815040.
The previous prime is 3434130215539. The next prime is 3434130215561. The reversal of 3434130215555 is 5555120314343.
3434130215555 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3434130215555 - 24 = 3434130215539 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2353755416 + ... + 2353756874.
It is an arithmetic number, because the mean of its divisors is an integer number (37334682000).
Almost surely, 23434130215555 is an apocalyptic number.
3434130215555 is a deficient number, since it is larger than the sum of its proper divisors (1344709080445).
3434130215555 is a wasteful number, since it uses less digits than its factorization.
3434130215555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2029.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 3434130215555 its reverse (5555120314343), we get a palindrome (8989250529898).
The spelling of 3434130215555 in words is "three trillion, four hundred thirty-four billion, one hundred thirty million, two hundred fifteen thousand, five hundred fifty-five".
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