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34344011035 = 5173241716427
BaseRepresentation
bin11111111111000100…
…000000010100011011
310021122111022112020201
4133333010000110123
51030314031323120
623435531203031
72324035164025
oct377704002433
9107574275221
1034344011035
11136243318a4
1267a58a6477
133314353a29
14193b34b015
15d601a340a
hex7ff10051b

34344011035 has 16 divisors (see below), whose sum is σ = 41470711776. Its totient is φ = 27303428608.

The previous prime is 34344011027. The next prime is 34344011059. The reversal of 34344011035 is 53011044343.

It is a cyclic number.

It is not a de Polignac number, because 34344011035 - 23 = 34344011027 is a prime.

It is a super-2 number, since 2×343440110352 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34344010994 and 34344011012.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2082492 + ... + 2098918.

It is an arithmetic number, because the mean of its divisors is an integer number (2591919486).

Almost surely, 234344011035 is an apocalyptic number.

34344011035 is a deficient number, since it is larger than the sum of its proper divisors (7126700741).

34344011035 is a wasteful number, since it uses less digits than its factorization.

34344011035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19022.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 34344011035 its reverse (53011044343), we get a palindrome (87355055378).

The spelling of 34344011035 in words is "thirty-four billion, three hundred forty-four million, eleven thousand, thirty-five".

Divisors: 1 5 173 865 2417 12085 16427 82135 418141 2090705 2841871 14209355 39704059 198520295 6868802207 34344011035