Base | Representation |
---|---|
bin | 110001111111101100001… |
… | …110111010100000101001 |
3 | 110011102222210221010010011 |
4 | 301333230032322200221 |
5 | 422242143400432103 |
6 | 11150151235451521 |
7 | 503134262606650 |
oct | 61775416724051 |
9 | 13142883833104 |
10 | 3435642202153 |
11 | 1105058502097 |
12 | 475a25756ba1 |
13 | 1bbc97445795 |
14 | bc4009b6197 |
15 | 5e580274d6d |
hex | 31fec3ba829 |
3435642202153 has 8 divisors (see below), whose sum is σ = 3926469036672. Its totient is φ = 2944820569056.
The previous prime is 3435642202151. The next prime is 3435642202163. The reversal of 3435642202153 is 3512022465343.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3435642202153 - 21 = 3435642202151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3435642202151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 236076 + ... + 2631922.
It is an arithmetic number, because the mean of its divisors is an integer number (490808629584).
Almost surely, 23435642202153 is an apocalyptic number.
It is an amenable number.
3435642202153 is a deficient number, since it is larger than the sum of its proper divisors (490826834519).
3435642202153 is a wasteful number, since it uses less digits than its factorization.
3435642202153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2600711.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 3435642202153 its reverse (3512022465343), we get a palindrome (6947664667496).
The spelling of 3435642202153 in words is "three trillion, four hundred thirty-five billion, six hundred forty-two million, two hundred two thousand, one hundred fifty-three".
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