Base | Representation |
---|---|
bin | 110010000011110111111… |
… | …000000011011011000011 |
3 | 110011212120202020001012122 |
4 | 302003313320003123003 |
5 | 422330342410100420 |
6 | 11152213002314455 |
7 | 503353455543521 |
oct | 62036770033303 |
9 | 13155522201178 |
10 | 3440132503235 |
11 | 1106a5212881a |
12 | 4768794b8a2b |
13 | 1bc53180477c |
14 | bc7090b9311 |
15 | 5e744599725 |
hex | 320f7e036c3 |
3440132503235 has 8 divisors (see below), whose sum is σ = 4138252304640. Its totient is φ = 2745377135424.
The previous prime is 3440132503229. The next prime is 3440132503321. The reversal of 3440132503235 is 5323052310443.
3440132503235 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3440132503235 - 28 = 3440132502979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3440132503195 and 3440132503204.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 841106147 + ... + 841110236.
It is an arithmetic number, because the mean of its divisors is an integer number (517281538080).
Almost surely, 23440132503235 is an apocalyptic number.
3440132503235 is a deficient number, since it is larger than the sum of its proper divisors (698119801405).
3440132503235 is a wasteful number, since it uses less digits than its factorization.
3440132503235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1682216797.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 3440132503235 its reverse (5323052310443), we get a palindrome (8763184813678).
The spelling of 3440132503235 in words is "three trillion, four hundred forty billion, one hundred thirty-two million, five hundred three thousand, two hundred thirty-five".
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