34404014101131 has 6 divisors (see below), whose sum is σ = 49694687034980. Its totient is φ = 22936009400748.

The previous prime is 34404014101049. The next prime is 34404014101151. The reversal of 34404014101131 is 13110141040443.

34404014101131 is a `hidden beast` number, since 3 + 4 + 404 + 0 + 141 + 0 + 113 + 1 = 666.

It is not a de Polignac number, because 34404014101131 - 2⁷ = 34404014101003 is a prime.

It is a super-2 number, since 2×34404014101131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34404014101095 and 34404014101104.

It is not an unprimeable number, because it can be changed into a prime (34404014101151) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1911334116721 + ... + 1911334116738.

Almost surely, 2^{34404014101131} is an apocalyptic number.

34404014101131 is a deficient number, since it is larger than the sum of its proper divisors (15290672933849).

34404014101131 is a wasteful number, since it uses less digits than its factorization.

34404014101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3822668233465 (or 3822668233462 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 34404014101131 its reverse (13110141040443), we get a palindrome (47514155141574).

The spelling of 34404014101131 in words is "thirty-four trillion, four hundred four billion, fourteen million, one hundred one thousand, one hundred thirty-one".