Base | Representation |
---|---|
bin | 110010000100111010001… |
… | …001101011110101000011 |
3 | 110011222110020111100020111 |
4 | 302010322021223311003 |
5 | 422340132032441233 |
6 | 11152515202452151 |
7 | 503423146645543 |
oct | 62047211536503 |
9 | 13158406440214 |
10 | 3441244421443 |
11 | 1107472843394 |
12 | 476b29964057 |
13 | 1bc67ac9913a |
14 | bc7b2a3b323 |
15 | 5e7abed6acd |
hex | 3213a26bd43 |
3441244421443 has 4 divisors (see below), whose sum is σ = 3442055466088. Its totient is φ = 3440433376800.
The previous prime is 3441244421437. The next prime is 3441244421471.
3441244421443 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3441244421443 - 217 = 3441244290371 is a prime.
It is a super-3 number, since 3×34412444214433 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3441244421396 and 3441244421405.
It is not an unprimeable number, because it can be changed into a prime (3441244421743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405515958 + ... + 405524443.
It is an arithmetic number, because the mean of its divisors is an integer number (860513866522).
Almost surely, 23441244421443 is an apocalyptic number.
3441244421443 is a deficient number, since it is larger than the sum of its proper divisors (811044645).
3441244421443 is an equidigital number, since it uses as much as digits as its factorization.
3441244421443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 811044644.
The product of its digits is 589824, while the sum is 40.
The spelling of 3441244421443 in words is "three trillion, four hundred forty-one billion, two hundred forty-four million, four hundred twenty-one thousand, four hundred forty-three".
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