344315211403 has 4 divisors (see below), whose sum is σ = 348463587528. Its totient is φ = 340166835280.

The previous prime is 344315211391. The next prime is 344315211433. The reversal of 344315211403 is 304112513443.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-344315211403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (344315211433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2074187938 + ... + 2074188103.

It is an arithmetic number, because the mean of its divisors is an integer number (87115896882).

Almost surely, 2^344315211403 is an apocalyptic number.

344315211403 is a deficient number, since it is larger than the sum of its proper divisors (4148376125).

344315211403 is an equidigital number, since it uses as much as digits as its factorization.

344315211403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4148376124.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 344315211403 its reverse (304112513443), we get a palindrome (648427724846).

The spelling of 344315211403 in words is "three hundred forty-four billion, three hundred fifteen million, two hundred eleven thousand, four hundred three".