Base | Representation |
---|---|
bin | 100000000101100000… |
… | …011000011101100011 |
3 | 10021221000201200121111 |
4 | 200011200120131203 |
5 | 1031024220111001 |
6 | 23454352204151 |
7 | 2326520062603 |
oct | 400540303543 |
9 | 107830650544 |
10 | 34452113251 |
11 | 1367a357676 |
12 | 6815b39657 |
13 | 333087333a |
14 | 194b84ac03 |
15 | d69908851 |
hex | 805818763 |
34452113251 has 4 divisors (see below), whose sum is σ = 34599976632. Its totient is φ = 34304249872.
The previous prime is 34452113243. The next prime is 34452113281. The reversal of 34452113251 is 15231125443.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15231125443 = 37 ⋅411652039.
It is a cyclic number.
It is not a de Polignac number, because 34452113251 - 23 = 34452113243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34452113281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73931341 + ... + 73931806.
It is an arithmetic number, because the mean of its divisors is an integer number (8649994158).
Almost surely, 234452113251 is an apocalyptic number.
34452113251 is a deficient number, since it is larger than the sum of its proper divisors (147863381).
34452113251 is a wasteful number, since it uses less digits than its factorization.
34452113251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147863380.
The product of its digits is 14400, while the sum is 31.
Adding to 34452113251 its reverse (15231125443), we get a palindrome (49683238694).
The spelling of 34452113251 in words is "thirty-four billion, four hundred fifty-two million, one hundred thirteen thousand, two hundred fifty-one".
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