Base | Representation |
---|---|
bin | 100111001100111001011000… |
… | …1110110011111100101010011 |
3 | 1200012220111001022100212001101 |
4 | 1032121302301312133211103 |
5 | 330144013120342310220 |
6 | 3221212103515245231 |
7 | 132426301321564660 |
oct | 11631626166374523 |
9 | 1605814038325041 |
10 | 344820138244435 |
11 | 9a963443661a77 |
12 | 32810552749817 |
13 | 11a53526963529 |
14 | 6121552da6a67 |
15 | 29ce86a7a030a |
hex | 1399cb1d9f953 |
344820138244435 has 16 divisors (see below), whose sum is σ = 479374219590336. Its totient is φ = 233209079797248.
The previous prime is 344820138244423. The next prime is 344820138244451. The reversal of 344820138244435 is 534442831028443.
It is a cyclic number.
It is not a de Polignac number, because 344820138244435 - 231 = 344817990760787 is a prime.
It is a super-2 number, since 2×3448201382444352 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67479476554 + ... + 67479481663.
It is an arithmetic number, because the mean of its divisors is an integer number (29960888724396).
Almost surely, 2344820138244435 is an apocalyptic number.
344820138244435 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
344820138244435 is a deficient number, since it is larger than the sum of its proper divisors (134554081345901).
344820138244435 is a wasteful number, since it uses less digits than its factorization.
344820138244435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134958958302.
The product of its (nonzero) digits is 35389440, while the sum is 55.
The spelling of 344820138244435 in words is "three hundred forty-four trillion, eight hundred twenty billion, one hundred thirty-eight million, two hundred forty-four thousand, four hundred thirty-five".
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