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34483254081 = 311494418027
BaseRepresentation
bin100000000111010111…
…001011001101000001
310022000012022210210120
4200013113023031001
51031110203112311
623501423450453
72330345552313
oct400727131501
9108005283716
1034483254081
11136959971a1
126824456a29
133337157673
141951a357b3
15d6c50a706
hex8075cb341

34483254081 has 4 divisors (see below), whose sum is σ = 45977672112. Its totient is φ = 22988836052.

The previous prime is 34483254059. The next prime is 34483254097. The reversal of 34483254081 is 18045238443.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 34483254081 - 211 = 34483252033 is a prime.

It is a super-2 number, since 2×344832540812 (a number of 22 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (34483254041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5747209011 + ... + 5747209016.

It is an arithmetic number, because the mean of its divisors is an integer number (11494418028).

Almost surely, 234483254081 is an apocalyptic number.

It is an amenable number.

34483254081 is a deficient number, since it is larger than the sum of its proper divisors (11494418031).

34483254081 is a wasteful number, since it uses less digits than its factorization.

34483254081 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11494418030.

The product of its (nonzero) digits is 368640, while the sum is 42.

The spelling of 34483254081 in words is "thirty-four billion, four hundred eighty-three million, two hundred fifty-four thousand, eighty-one".

Divisors: 1 3 11494418027 34483254081