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345131043546307 = 2437141621273511
BaseRepresentation
bin100111001111001010001010…
…1010000000110010011000011
31200021000012112211112121121211
41032132110111100012103003
5330214111334121440212
63222011002415030551
7132460615666212334
oct11636242520062303
91607005484477554
10345131043546307
119aa73287596a47
123286086020b457
1311a76943bb1285
1461326085a828b
1529d79b55449a7
hex139e5154064c3

345131043546307 has 4 divisors (see below), whose sum is σ = 345272664822256. Its totient is φ = 344989422270360.

The previous prime is 345131043546287. The next prime is 345131043546319. The reversal of 345131043546307 is 703645340131543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 345131043546307 - 239 = 344581287732419 is a prime.

It is a super-3 number, since 3×3451310435463073 (a number of 45 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (345131043646307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70810634319 + ... + 70810639192.

It is an arithmetic number, because the mean of its divisors is an integer number (86318166205564).

Almost surely, 2345131043546307 is an apocalyptic number.

345131043546307 is a deficient number, since it is larger than the sum of its proper divisors (141621275949).

345131043546307 is a wasteful number, since it uses less digits than its factorization.

345131043546307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141621275948.

The product of its (nonzero) digits is 5443200, while the sum is 49.

The spelling of 345131043546307 in words is "three hundred forty-five trillion, one hundred thirty-one billion, forty-three million, five hundred forty-six thousand, three hundred seven".

Divisors: 1 2437 141621273511 345131043546307