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34513143403 = 179192810857
BaseRepresentation
bin100000001001001001…
…001100011001101011
310022002021120100020111
4200021021030121223
51031140331042103
623504412235151
72331160610224
oct401111143153
9108067510214
1034513143403
1113700851512
12683246bab7
1333403c115b
1419559b624b
15d6ee6186d
hex80924c66b

34513143403 has 4 divisors (see below), whose sum is σ = 34705954440. Its totient is φ = 34320332368.

The previous prime is 34513143367. The next prime is 34513143409. The reversal of 34513143403 is 30434131543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34513143403 is a prime.

It is a super-3 number, since 3×345131434033 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34513143409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96405250 + ... + 96405607.

It is an arithmetic number, because the mean of its divisors is an integer number (8676488610).

Almost surely, 234513143403 is an apocalyptic number.

34513143403 is a deficient number, since it is larger than the sum of its proper divisors (192811037).

34513143403 is a wasteful number, since it uses less digits than its factorization.

34513143403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192811036.

The product of its (nonzero) digits is 25920, while the sum is 31.

Adding to 34513143403 its reverse (30434131543), we get a palindrome (64947274946).

The spelling of 34513143403 in words is "thirty-four billion, five hundred thirteen million, one hundred forty-three thousand, four hundred three".

Divisors: 1 179 192810857 34513143403