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34543143433 = 298314351119
BaseRepresentation
bin100000001010111011…
…101000101000001001
310022011101000111112201
4200022323220220021
51031221021042213
623511403240201
72332003605661
oct401273505011
9108141014481
1034543143433
1113716781a27
126840519061
133346696156
1419599851a1
15d728da6dd
hex80aee8a09

34543143433 has 8 divisors (see below), whose sum is σ = 36164822400. Its totient is φ = 32950166928.

The previous prime is 34543143407. The next prime is 34543143443. The reversal of 34543143433 is 33434134543.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 34543143433 - 213 = 34543135241 is a prime.

It is a super-2 number, since 2×345431434332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34543143392 and 34543143401.

It is not an unprimeable number, because it can be changed into a prime (34543143443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7173153 + ... + 7177966.

It is an arithmetic number, because the mean of its divisors is an integer number (4520602800).

Almost surely, 234543143433 is an apocalyptic number.

It is an amenable number.

34543143433 is a deficient number, since it is larger than the sum of its proper divisors (1621678967).

34543143433 is a wasteful number, since it uses less digits than its factorization.

34543143433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14351231.

The product of its digits is 311040, while the sum is 37.

Adding to 34543143433 its reverse (33434134543), we get a palindrome (67977277976).

The spelling of 34543143433 in words is "thirty-four billion, five hundred forty-three million, one hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 29 83 2407 14351119 416182451 1191142877 34543143433