Base | Representation |
---|---|
bin | 1111101101010111001111… |
… | …10100010010110110100011 |
3 | 11112022101010212220211202012 |
4 | 13312223213310102312203 |
5 | 14011432121124140120 |
6 | 201245145121143135 |
7 | 10163502632215301 |
oct | 766534764226643 |
9 | 145271125824665 |
10 | 34544016240035 |
11 | 100090426747a5 |
12 | 3a5aa4118aaab |
13 | 16376435245a3 |
14 | 875d2165b271 |
15 | 3ed880c811c5 |
hex | 1f6ae7d12da3 |
34544016240035 has 8 divisors (see below), whose sum is σ = 41470258635456. Its totient is φ = 27623586893760.
The previous prime is 34544016240007. The next prime is 34544016240053. The reversal of 34544016240035 is 53004261044543.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-34544016240035 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34544016239974 and 34544016240001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1453249211 + ... + 1453272980.
It is an arithmetic number, because the mean of its divisors is an integer number (5183782329432).
Almost surely, 234544016240035 is an apocalyptic number.
34544016240035 is a deficient number, since it is larger than the sum of its proper divisors (6926242395421).
34544016240035 is a wasteful number, since it uses less digits than its factorization.
34544016240035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2906524573.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 34544016240035 its reverse (53004261044543), we get a palindrome (87548277284578).
The spelling of 34544016240035 in words is "thirty-four trillion, five hundred forty-four billion, sixteen million, two hundred forty thousand, thirty-five".
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