Base | Representation |
---|---|
bin | 1111110010011110101101… |
… | …11100100000100111000011 |
3 | 11112221011221102120200112201 |
4 | 13321033112330200213003 |
5 | 14022322201132340003 |
6 | 201502022424334031 |
7 | 10212265450523164 |
oct | 771172674404703 |
9 | 145834842520481 |
10 | 34719826840003 |
11 | 1007666111a6a8 |
12 | 3a88b27914317 |
13 | 164b0b1231ab6 |
14 | 88063ccbd76b |
15 | 4032207a0b1d |
hex | 1f93d6f209c3 |
34719826840003 has 4 divisors (see below), whose sum is σ = 34719848399848. Its totient is φ = 34719805280160.
The previous prime is 34719826839979. The next prime is 34719826840007. The reversal of 34719826840003 is 30004862891743.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34719826840003 is a prime.
It is a super-2 number, since 2×347198268400032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34719826840007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8150553 + ... + 11656378.
It is an arithmetic number, because the mean of its divisors is an integer number (8679962099962).
Almost surely, 234719826840003 is an apocalyptic number.
34719826840003 is a deficient number, since it is larger than the sum of its proper divisors (21559845).
34719826840003 is a wasteful number, since it uses less digits than its factorization.
34719826840003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21559844.
The product of its (nonzero) digits is 6967296, while the sum is 55.
The spelling of 34719826840003 in words is "thirty-four trillion, seven hundred nineteen billion, eight hundred twenty-six million, eight hundred forty thousand, three".
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