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34832295313 = 113308250401
BaseRepresentation
bin100000011100001010…
…101010010110010001
310022220112002221100121
4200130022222112101
51032314031422223
624000212550241
72342114424244
oct403412522621
9108815087317
1034832295313
1113854a17022
126901322381
13339156633a
14198613325b
15d8cea515d
hex81c2aa591

34832295313 has 4 divisors (see below), whose sum is σ = 35140545828. Its totient is φ = 34524044800.

The previous prime is 34832295293. The next prime is 34832295317. The reversal of 34832295313 is 31359223843.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31359223843 = 49163868073.

It can be written as a sum of positive squares in 2 ways, for example, as 846635409 + 33985659904 = 29097^2 + 184352^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34832295313 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 34832295313.

It is not an unprimeable number, because it can be changed into a prime (34832295317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154125088 + ... + 154125313.

It is an arithmetic number, because the mean of its divisors is an integer number (8785136457).

Almost surely, 234832295313 is an apocalyptic number.

It is an amenable number.

34832295313 is a deficient number, since it is larger than the sum of its proper divisors (308250515).

34832295313 is a wasteful number, since it uses less digits than its factorization.

34832295313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 308250514.

The product of its digits is 466560, while the sum is 43.

The spelling of 34832295313 in words is "thirty-four billion, eight hundred thirty-two million, two hundred ninety-five thousand, three hundred thirteen".

Divisors: 1 113 308250401 34832295313