Base | Representation |
---|---|
bin | 1010001011111110001… |
… | …11111101110001011011 |
3 | 1020110110212001201102101 |
4 | 11011333013331301123 |
5 | 21213322414123220 |
6 | 424444353344231 |
7 | 34200643434400 |
oct | 5057707756133 |
9 | 1213425051371 |
10 | 350025145435 |
11 | 1254990844a9 |
12 | 57a06868077 |
13 | 27012b63a94 |
14 | 12d26d3a2a7 |
15 | 918936e30a |
hex | 517f1fdc5b |
350025145435 has 12 divisors (see below), whose sum is σ = 488606529888. Its totient is φ = 240017242416.
The previous prime is 350025145433. The next prime is 350025145451. The reversal of 350025145435 is 534541520053.
It is not a de Polignac number, because 350025145435 - 21 = 350025145433 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 350025145394 and 350025145403.
It is not an unprimeable number, because it can be changed into a prime (350025145433) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 714336787 + ... + 714337276.
It is an arithmetic number, because the mean of its divisors is an integer number (40717210824).
Almost surely, 2350025145435 is an apocalyptic number.
350025145435 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
350025145435 is a deficient number, since it is larger than the sum of its proper divisors (138581384453).
350025145435 is a wasteful number, since it uses less digits than its factorization.
350025145435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1428674082 (or 1428674075 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 37.
Adding to 350025145435 its reverse (534541520053), we get a palindrome (884566665488).
The spelling of 350025145435 in words is "three hundred fifty billion, twenty-five million, one hundred forty-five thousand, four hundred thirty-five".
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