350031113 has 4 divisors (see below), whose sum is σ = 350487060. Its totient is φ = 349575168.

The previous prime is 350031079. The next prime is 350031119. The reversal of 350031113 is 311130053.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311130053 = 13 ⋅23933081.

It can be written as a sum of positive squares in 2 ways, for example, as 163763209 + 186267904 = 12797^2 + 13648^2 .

It is a cyclic number.

It is not a de Polignac number, because 350031113 - 2¹⁰ = 350030089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 350031091 and 350031100.

It is not an unprimeable number, because it can be changed into a prime (350031119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226820 + ... + 228357.

It is an arithmetic number, because the mean of its divisors is an integer number (87621765).

Almost surely, 2^350031113 is an apocalyptic number.

It is an amenable number.

350031113 is a deficient number, since it is larger than the sum of its proper divisors (455947).

350031113 is an equidigital number, since it uses as much as digits as its factorization.

350031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455946.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 350031113 is about 18709.1184452929. The cubic root of 350031113 is about 704.7507547407.

Adding to 350031113 its reverse (311130053), we get a palindrome (661161166).

The spelling of 350031113 in words is "three hundred fifty million, thirty-one thousand, one hundred thirteen".