351144441153 has 12 divisors (see below), whose sum is σ = 553318513488. Its totient is φ = 212814812760.

The previous prime is 351144441149. The next prime is 351144441199.

351144441153 is a `hidden beast` number, since 3 + 51 + 14 + 4 + 441 + 153 = 666.

351144441153 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 351144441153 - 2² = 351144441149 is a prime.

It is not an unprimeable number, because it can be changed into a prime (351144441553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1773456675 + ... + 1773456872.

It is an arithmetic number, because the mean of its divisors is an integer number (46109876124).

Almost surely, 2^351144441153 is an apocalyptic number.

351144441153 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

351144441153 is a deficient number, since it is larger than the sum of its proper divisors (202174072335).

351144441153 is a wasteful number, since it uses less digits than its factorization.

351144441153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3546913564 (or 3546913561 counting only the distinct ones).

The product of its digits is 57600, while the sum is 36.

It can be divided in two parts, 351144 and 441153, that added together give a palindrome (792297).

The spelling of 351144441153 in words is "three hundred fifty-one billion, one hundred forty-four million, four hundred forty-one thousand, one hundred fifty-three".