35130035 has 4 divisors (see below), whose sum is σ = 42156048. Its totient is φ = 28104024.

The previous prime is 35130013. The next prime is 35130061. The reversal of 35130035 is 53003153.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 35130035 - 2¹⁰ = 35129011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 35129989 and 35130016.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3512999 + ... + 3513008.

It is an arithmetic number, because the mean of its divisors is an integer number (10539012).

Almost surely, 2^35130035 is an apocalyptic number.

35130035 is a deficient number, since it is larger than the sum of its proper divisors (7026013).

35130035 is an equidigital number, since it uses as much as digits as its factorization.

35130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7026012.

The product of its (nonzero) digits is 675, while the sum is 20.

The square root of 35130035 is about 5927.0595576559. The cubic root of 35130035 is about 327.5112285644.

Adding to 35130035 its reverse (53003153), we get a palindrome (88133188).

The spelling of 35130035 in words is "thirty-five million, one hundred thirty thousand, thirty-five".