Base | Representation |
---|---|
bin | 100000101110000111… |
… | …010101001100010001 |
3 | 10100200111201020221200 |
4 | 200232013111030101 |
5 | 1033423123141423 |
6 | 24050130541413 |
7 | 2352432034632 |
oct | 405607251421 |
9 | 110614636850 |
10 | 35133412113 |
11 | 13999993588 |
12 | 6986137869 |
13 | 340ba65567 |
14 | 19b4117889 |
15 | da9634d43 |
hex | 82e1d5311 |
35133412113 has 12 divisors (see below), whose sum is σ = 50958838788. Its totient is φ = 23325085440.
The previous prime is 35133412091. The next prime is 35133412121. The reversal of 35133412113 is 31121433153.
35133412113 is a `hidden beast` number, since 3 + 5 + 133 + 412 + 113 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 10342279809 + 24791132304 = 101697^2 + 157452^2 .
It is not a de Polignac number, because 35133412113 - 25 = 35133412081 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (35133412813) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8096820 + ... + 8101157.
It is an arithmetic number, because the mean of its divisors is an integer number (4246569899).
Almost surely, 235133412113 is an apocalyptic number.
It is an amenable number.
35133412113 is a deficient number, since it is larger than the sum of its proper divisors (15825426675).
35133412113 is a wasteful number, since it uses less digits than its factorization.
35133412113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16198224 (or 16198221 counting only the distinct ones).
The product of its digits is 3240, while the sum is 27.
Adding to 35133412113 its reverse (31121433153), we get a palindrome (66254845266).
The spelling of 35133412113 in words is "thirty-five billion, one hundred thirty-three million, four hundred twelve thousand, one hundred thirteen".
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