Base | Representation |
---|---|
bin | 1111111110101111010011… |
… | …10100111011001110110001 |
3 | 11121102110012020001022202202 |
4 | 13333113221310323032301 |
5 | 14101222332401222001 |
6 | 202423324203352545 |
7 | 10254566663032220 |
oct | 777275164731661 |
9 | 147373166038682 |
10 | 35141050414001 |
11 | 102192659192a4 |
12 | 3b366a2822755 |
13 | 167ba2c8a433c |
14 | 896b9ba72cb7 |
15 | 40e17555a96b |
hex | 1ff5e9d3b3b1 |
35141050414001 has 4 divisors (see below), whose sum is σ = 40161200473152. Its totient is φ = 30120900354852.
The previous prime is 35141050413899. The next prime is 35141050414007. The reversal of 35141050414001 is 10041405014153.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 35141050414001 - 214 = 35141050397617 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (35141050414007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2510075029565 + ... + 2510075029578.
It is an arithmetic number, because the mean of its divisors is an integer number (10040300118288).
Almost surely, 235141050414001 is an apocalyptic number.
It is an amenable number.
35141050414001 is a deficient number, since it is larger than the sum of its proper divisors (5020150059151).
35141050414001 is an equidigital number, since it uses as much as digits as its factorization.
35141050414001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5020150059150.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 35141050414001 its reverse (10041405014153), we get a palindrome (45182455428154).
The spelling of 35141050414001 in words is "thirty-five trillion, one hundred forty-one billion, fifty million, four hundred fourteen thousand, one".
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