Base | Representation |
---|---|
bin | 110011001000111111001… |
… | …000011110010101101001 |
3 | 110102222010120022010121120 |
4 | 303020333020132111221 |
5 | 430034333130343103 |
6 | 11250244442525453 |
7 | 511621452545325 |
oct | 63107710362551 |
9 | 13388116263546 |
10 | 3514342434153 |
11 | 113547375a241 |
12 | 48912a206889 |
13 | 1c652a1c40b5 |
14 | c2148c90985 |
15 | 6163959c253 |
hex | 3323f21e569 |
3514342434153 has 4 divisors (see below), whose sum is σ = 4685789912208. Its totient is φ = 2342894956100.
The previous prime is 3514342434139. The next prime is 3514342434157.
3514342434153 is nontrivially palindromic in base 10.
3514342434153 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3514342434153 - 28 = 3514342433897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3514342434157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 585723739023 + ... + 585723739028.
It is an arithmetic number, because the mean of its divisors is an integer number (1171447478052).
Almost surely, 23514342434153 is an apocalyptic number.
It is an amenable number.
3514342434153 is a deficient number, since it is larger than the sum of its proper divisors (1171447478055).
3514342434153 is a wasteful number, since it uses less digits than its factorization.
3514342434153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1171447478054.
The product of its digits is 1036800, while the sum is 42.
The spelling of 3514342434153 in words is "three trillion, five hundred fourteen billion, three hundred forty-two million, four hundred thirty-four thousand, one hundred fifty-three".
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