Base | Representation |
---|---|
bin | 100000101111001101… |
… | …010010010000000001 |
3 | 10100201210012221000001 |
4 | 200233031102100001 |
5 | 1033442322001040 |
6 | 24052024000001 |
7 | 2353043642401 |
oct | 405715222001 |
9 | 110653187001 |
10 | 35151750145 |
11 | 139a9279186 |
12 | 6990300001 |
13 | 34127b6375 |
14 | 19b672c801 |
15 | dab05859a |
hex | 82f352401 |
35151750145 has 4 divisors (see below), whose sum is σ = 42182100180. Its totient is φ = 28121400112.
The previous prime is 35151750131. The next prime is 35151750173. The reversal of 35151750145 is 54105715153.
It is a Cunningham number, because it is equal to 1874882+1.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54105715153 = 7 ⋅7729387879.
It can be written as a sum of positive squares in 2 ways, for example, as 12654450064 + 22497300081 = 112492^2 + 149991^2 .
It is a cyclic number.
It is not a de Polignac number, because 35151750145 - 211 = 35151748097 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3515175010 + ... + 3515175019.
It is an arithmetic number, because the mean of its divisors is an integer number (10545525045).
Almost surely, 235151750145 is an apocalyptic number.
It is an amenable number.
35151750145 is a deficient number, since it is larger than the sum of its proper divisors (7030350035).
35151750145 is an equidigital number, since it uses as much as digits as its factorization.
35151750145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7030350034.
The product of its (nonzero) digits is 52500, while the sum is 37.
The spelling of 35151750145 in words is "thirty-five billion, one hundred fifty-one million, seven hundred fifty thousand, one hundred forty-five".
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