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352113440433 = 32294631106993
BaseRepresentation
bin1010001111110111001…
…10001011011010110001
31020122212101120002121120
411013323212023122301
521232112020043213
6425431513012453
734303461601116
oct5077346133261
91218771502546
10352113440433
1112636a948437
12582aa0b4129
13272866b3cb1
141308441a90d
15925c873423
hex51fb98b6b1

352113440433 has 16 divisors (see below), whose sum is σ = 472553598720. Its totient is φ = 233212218624.

The previous prime is 352113440431. The next prime is 352113440447. The reversal of 352113440433 is 334044311253.

It is not a de Polignac number, because 352113440433 - 21 = 352113440431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 352113440394 and 352113440403.

It is not an unprimeable number, because it can be changed into a prime (352113440431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 235416 + ... + 871577.

It is an arithmetic number, because the mean of its divisors is an integer number (29534599920).

Almost surely, 2352113440433 is an apocalyptic number.

It is an amenable number.

352113440433 is a deficient number, since it is larger than the sum of its proper divisors (120440158287).

352113440433 is a wasteful number, since it uses less digits than its factorization.

352113440433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1107688.

The product of its (nonzero) digits is 51840, while the sum is 33.

Adding to 352113440433 its reverse (334044311253), we get a palindrome (686157751686).

The spelling of 352113440433 in words is "three hundred fifty-two billion, one hundred thirteen million, four hundred forty thousand, four hundred thirty-three".

Divisors: 1 3 229 463 687 1389 106027 318081 1106993 3320979 253501397 512537759 760504191 1537613277 117371146811 352113440433