Base | Representation |
---|---|
bin | 10000000001011010110011… |
… | …10010001010111001011001 |
3 | 11121202020211220222000021211 |
4 | 20000231121302022321121 |
5 | 14104224414000200040 |
6 | 202533512343503121 |
7 | 10264336430405413 |
oct | 1000553162127131 |
9 | 147666756860254 |
10 | 35233123053145 |
11 | 1025431348a8a6 |
12 | 3b504b9757aa1 |
13 | 1687613c247c4 |
14 | 89b413d379b3 |
15 | 4117638478ea |
hex | 200b59c8ae59 |
35233123053145 has 16 divisors (see below), whose sum is σ = 44766991716480. Its totient is φ = 26528350561024.
The previous prime is 35233123053131. The next prime is 35233123053187. The reversal of 35233123053145 is 54135032133253.
It is not a de Polignac number, because 35233123053145 - 215 = 35233123020377 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 35233123053098 and 35233123053107.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21332724 + ... + 22924906.
It is an arithmetic number, because the mean of its divisors is an integer number (2797936982280).
Almost surely, 235233123053145 is an apocalyptic number.
It is an amenable number.
35233123053145 is a deficient number, since it is larger than the sum of its proper divisors (9533868663335).
35233123053145 is a wasteful number, since it uses less digits than its factorization.
35233123053145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1852544.
The product of its (nonzero) digits is 486000, while the sum is 40.
Adding to 35233123053145 its reverse (54135032133253), we get a palindrome (89368155186398).
The spelling of 35233123053145 in words is "thirty-five trillion, two hundred thirty-three billion, one hundred twenty-three million, fifty-three thousand, one hundred forty-five".
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