3525061341131 has 4 divisors (see below), whose sum is σ = 3845521463064. Its totient is φ = 3204601219200.

The previous prime is 3525061341101. The next prime is 3525061341209. The reversal of 3525061341131 is 1311431605253.

3525061341131 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3525061341131 is a prime.

It is a super-2 number, since 2×3525061341131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3525061341091 and 3525061341100.

It is not an unprimeable number, because it can be changed into a prime (3525061341101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160230060950 + ... + 160230060971.

It is an arithmetic number, because the mean of its divisors is an integer number (961380365766).

Almost surely, 2^{3525061341131} is an apocalyptic number.

3525061341131 is a deficient number, since it is larger than the sum of its proper divisors (320460121933).

3525061341131 is a wasteful number, since it uses less digits than its factorization.

3525061341131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320460121932.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 3525061341131 its reverse (1311431605253), we get a palindrome (4836492946384).

The spelling of 3525061341131 in words is "three trillion, five hundred twenty-five billion, sixty-one million, three hundred forty-one thousand, one hundred thirty-one".