353430401341513 has 4 divisors (see below), whose sum is σ = 353750827817088. Its totient is φ = 353109974865940.

The previous prime is 353430401341427. The next prime is 353430401341519. The reversal of 353430401341513 is 315143104034353.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-353430401341513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (353430401341519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160213236133 + ... + 160213238338.

It is an arithmetic number, because the mean of its divisors is an integer number (88437706954272).

Almost surely, 2^{353430401341513} is an apocalyptic number.

It is an amenable number.

353430401341513 is a deficient number, since it is larger than the sum of its proper divisors (320426475575).

353430401341513 is a wasteful number, since it uses less digits than its factorization.

353430401341513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320426475574.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 353430401341513 its reverse (315143104034353), we get a palindrome (668573505375866).

The spelling of 353430401341513 in words is "three hundred fifty-three trillion, four hundred thirty billion, four hundred one million, three hundred forty-one thousand, five hundred thirteen".