3543403440403 has 4 divisors (see below), whose sum is σ = 3543410280280. Its totient is φ = 3543396600528.

The previous prime is 3543403440373. The next prime is 3543403440419. The reversal of 3543403440403 is 3040443043453.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3543403440403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3543403440503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2572938 + ... + 3702271.

It is an arithmetic number, because the mean of its divisors is an integer number (885852570070).

Almost surely, 2^{3543403440403} is an apocalyptic number.

3543403440403 is a deficient number, since it is larger than the sum of its proper divisors (6839877).

3543403440403 is an equidigital number, since it uses as much as digits as its factorization.

3543403440403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6839876.

The product of its (nonzero) digits is 414720, while the sum is 37.

Adding to 3543403440403 its reverse (3040443043453), we get a palindrome (6583846483856).

The spelling of 3543403440403 in words is "three trillion, five hundred forty-three billion, four hundred three million, four hundred forty thousand, four hundred three".