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354893231953 = 1327299479381
BaseRepresentation
bin1010010101000010100…
…10001111011101010001
31020221001010020010201001
411022201102033131101
521303310131410303
6431011413342001
734432404461431
oct5124122173521
91227033203631
10354893231953
11127566a829a7
1258945037901
132760a586c50
14132696a02c1
15937191a31d
hex52a148f751

354893231953 has 4 divisors (see below), whose sum is σ = 382192711348. Its totient is φ = 327593752560.

The previous prime is 354893231947. The next prime is 354893231969. The reversal of 354893231953 is 359132398453.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 14575008529 + 340318223424 = 120727^2 + 583368^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354893231953 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 354893231894 and 354893231903.

It is not an unprimeable number, because it can be changed into a prime (354893231933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13649739678 + ... + 13649739703.

It is an arithmetic number, because the mean of its divisors is an integer number (95548177837).

Almost surely, 2354893231953 is an apocalyptic number.

It is an amenable number.

354893231953 is a deficient number, since it is larger than the sum of its proper divisors (27299479395).

354893231953 is a wasteful number, since it uses less digits than its factorization.

354893231953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27299479394.

The product of its digits is 10497600, while the sum is 55.

The spelling of 354893231953 in words is "three hundred fifty-four billion, eight hundred ninety-three million, two hundred thirty-one thousand, nine hundred fifty-three".

Divisors: 1 13 27299479381 354893231953