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3682609350433 = 13283277642341
BaseRepresentation
bin110101100101101100100…
…111110100011100100001
3111001001110101012010210221
4311211230213310130201
5440313440443203213
611455433430523041
7530026331000266
oct65455447643441
914031411163727
103682609350433
11119a870a77a12
124b586a506481
1320936508a150
14ca34c6ad26d
1565bd6bab38d
hex3596c9f4721

3682609350433 has 4 divisors (see below), whose sum is σ = 3965886992788. Its totient is φ = 3399331708080.

The previous prime is 3682609350389. The next prime is 3682609350457. The reversal of 3682609350433 is 3340539062863.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1331330591889 + 2351278758544 = 1153833^2 + 1533388^2 .

It is a cyclic number.

It is not a de Polignac number, because 3682609350433 - 237 = 3545170396961 is a prime.

It is a super-2 number, since 2×36826093504332 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3682609351433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141638821158 + ... + 141638821183.

It is an arithmetic number, because the mean of its divisors is an integer number (991471748197).

Almost surely, 23682609350433 is an apocalyptic number.

It is an amenable number.

3682609350433 is a deficient number, since it is larger than the sum of its proper divisors (283277642355).

3682609350433 is a wasteful number, since it uses less digits than its factorization.

3682609350433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283277642354.

The product of its (nonzero) digits is 8398080, while the sum is 52.

The spelling of 3682609350433 in words is "three trillion, six hundred eighty-two billion, six hundred nine million, three hundred fifty thousand, four hundred thirty-three".

Divisors: 1 13 283277642341 3682609350433