Base | Representation |
---|---|
bin | 110110011110101111001… |
… | …011011011110100000001 |
3 | 111020220112201200011212020 |
4 | 312132233023123310001 |
5 | 442314404003300441 |
6 | 11543523052552053 |
7 | 534325141616325 |
oct | 66365713336401 |
9 | 14226481604766 |
10 | 3743855525121 |
11 | 121383a929508 |
12 | 505701782629 |
13 | 212075a579ba |
14 | cd2bc871985 |
15 | 675bda1ae66 |
hex | 367af2dbd01 |
3743855525121 has 8 divisors (see below), whose sum is σ = 4997591619840. Its totient is φ = 2493011556912.
The previous prime is 3743855525029. The next prime is 3743855525143. The reversal of 3743855525121 is 1215255583473.
3743855525121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3743855525121 - 27 = 3743855524993 is a prime.
It is a super-3 number, since 3×37438555251213 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (3743855525191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 723028606 + ... + 723033783.
It is an arithmetic number, because the mean of its divisors is an integer number (624698952480).
Almost surely, 23743855525121 is an apocalyptic number.
It is an amenable number.
3743855525121 is a deficient number, since it is larger than the sum of its proper divisors (1253736094719).
3743855525121 is a wasteful number, since it uses less digits than its factorization.
3743855525121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1446063255.
The product of its digits is 5040000, while the sum is 51.
The spelling of 3743855525121 in words is "three trillion, seven hundred forty-three billion, eight hundred fifty-five million, five hundred twenty-five thousand, one hundred twenty-one".
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