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3804770717113 = 7948161654647
BaseRepresentation
bin110111010111011110000…
…000011100110110111001
3111110201210000100120000011
4313113132000130312321
5444314132300421423
612031515412541521
7541612523325262
oct67273600346671
914421700316004
103804770717113
111237659974893
125154820218a1
13217a32c9a3c2
14d221aab7969
1568e8679bb0d
hex375de01cdb9

3804770717113 has 4 divisors (see below), whose sum is σ = 3852932371840. Its totient is φ = 3756609062388.

The previous prime is 3804770717093. The next prime is 3804770717129. The reversal of 3804770717113 is 3117170774083.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3804770717113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3804770717183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24080827245 + ... + 24080827402.

It is an arithmetic number, because the mean of its divisors is an integer number (963233092960).

Almost surely, 23804770717113 is an apocalyptic number.

It is an amenable number.

3804770717113 is a deficient number, since it is larger than the sum of its proper divisors (48161654727).

3804770717113 is an equidigital number, since it uses as much as digits as its factorization.

3804770717113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48161654726.

The product of its (nonzero) digits is 691488, while the sum is 49.

The spelling of 3804770717113 in words is "three trillion, eight hundred four billion, seven hundred seventy million, seven hundred seventeen thousand, one hundred thirteen".

Divisors: 1 79 48161654647 3804770717113