Base | Representation |
---|---|
bin | 101011011100011100101111… |
… | …0001011011001101010000011 |
3 | 1212010001102022001011010101211 |
4 | 1112320321132023121222003 |
5 | 400042003304030210113 |
6 | 3432425340015510551 |
7 | 143330564002343152 |
oct | 12670713613315203 |
9 | 1763042261133354 |
10 | 382142000241283 |
11 | 10084256a795457 |
12 | 36a3981a828457 |
13 | 1352cab38c04b9 |
14 | 6a51ab2dc7599 |
15 | 2e2a5cc8a5b3d |
hex | 15b8e5e2d9a83 |
382142000241283 has 4 divisors (see below), whose sum is σ = 388618983296280. Its totient is φ = 375665017186288.
The previous prime is 382142000241251. The next prime is 382142000241293.
382142000241283 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 382142000241283 - 25 = 382142000241251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (382142000241293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3238491527410 + ... + 3238491527527.
It is an arithmetic number, because the mean of its divisors is an integer number (97154745824070).
Almost surely, 2382142000241283 is an apocalyptic number.
382142000241283 is a deficient number, since it is larger than the sum of its proper divisors (6476983054997).
382142000241283 is an equidigital number, since it uses as much as digits as its factorization.
382142000241283 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6476983054996.
The product of its (nonzero) digits is 147456, while the sum is 40.
It can be divided in two parts, 382142000 and 241283, that added together give a palindrome (382383283).
The spelling of 382142000241283 in words is "three hundred eighty-two trillion, one hundred forty-two billion, two hundred forty-one thousand, two hundred eighty-three".
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