Base | Representation |
---|---|
bin | 110111111000010110101… |
… | …011000100010110001011 |
3 | 111121002220212011110200120 |
4 | 313320112223010112023 |
5 | 1000403441233320441 |
6 | 12100035310034323 |
7 | 544302535136613 |
oct | 67702653042613 |
9 | 14532825143616 |
10 | 3840081151371 |
11 | 1250629776763 |
12 | 5202974a89a3 |
13 | 21b16c60329a |
14 | d3c0a511a43 |
15 | 69d516ec966 |
hex | 37e16ac458b |
3840081151371 has 4 divisors (see below), whose sum is σ = 5120108201832. Its totient is φ = 2560054100912.
The previous prime is 3840081151369. The next prime is 3840081151373. The reversal of 3840081151371 is 1731511800483.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (3840081151369) and next prime (3840081151373).
It is a cyclic number.
It is not a de Polignac number, because 3840081151371 - 21 = 3840081151369 is a prime.
It is a super-2 number, since 2×38400811513712 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3840081151373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640013525226 + ... + 640013525231.
It is an arithmetic number, because the mean of its divisors is an integer number (1280027050458).
Almost surely, 23840081151371 is an apocalyptic number.
3840081151371 is a deficient number, since it is larger than the sum of its proper divisors (1280027050461).
3840081151371 is a wasteful number, since it uses less digits than its factorization.
3840081151371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1280027050460.
The product of its (nonzero) digits is 80640, while the sum is 42.
The spelling of 3840081151371 in words is "three trillion, eight hundred forty billion, eighty-one million, one hundred fifty-one thousand, three hundred seventy-one".
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