38404025133035 has 8 divisors (see below), whose sum is σ = 46090511977536. Its totient is φ = 30719432227840.

The previous prime is 38404025133017. The next prime is 38404025133059. The reversal of 38404025133035 is 53033152040483.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 38404025133035 - 2⁶ = 38404025132971 is a prime.

It is a super-2 number, since 2×38404025133035² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 38404025132983 and 38404025133001.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 473440214 + ... + 473521323.

It is an arithmetic number, because the mean of its divisors is an integer number (5761313997192).

Almost surely, 2^{38404025133035} is an apocalyptic number.

38404025133035 is a deficient number, since it is larger than the sum of its proper divisors (7686486844501).

38404025133035 is an equidigital number, since it uses as much as digits as its factorization.

38404025133035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 946969653.

The product of its (nonzero) digits is 518400, while the sum is 41.

The spelling of 38404025133035 in words is "thirty-eight trillion, four hundred four billion, twenty-five million, one hundred thirty-three thousand, thirty-five".