3841631401 has 4 divisors (see below), whose sum is σ = 3842187904. Its totient is φ = 3841074900.

The previous prime is 3841631393. The next prime is 3841631459. The reversal of 3841631401 is 1041361483.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1041361483 = 6907 ⋅150769.

It is a cyclic number.

It is not a de Polignac number, because 3841631401 - 2³ = 3841631393 is a prime.

It is a super-2 number, since 2×3841631401² = 29516263642298445602, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3841631201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 267765 + ... + 281746.

It is an arithmetic number, because the mean of its divisors is an integer number (960546976).

Almost surely, 2^3841631401 is an apocalyptic number.

It is an amenable number.

3841631401 is a deficient number, since it is larger than the sum of its proper divisors (556503).

3841631401 is an equidigital number, since it uses as much as digits as its factorization.

3841631401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 556502.

The product of its (nonzero) digits is 6912, while the sum is 31.

The square root of 3841631401 is about 61980.8954517438. The cubic root of 3841631401 is about 1566.1687861462.

Adding to 3841631401 its reverse (1041361483), we get a palindrome (4882992884).

The spelling of 3841631401 in words is "three billion, eight hundred forty-one million, six hundred thirty-one thousand, four hundred one".