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3842834142057 = 31280944714019
BaseRepresentation
bin110111111010111010110…
…000111001001101101001
3111121101000201101212221120
4313322322300321031221
51000430111020021212
612101212412125453
7544431004154541
oct67727260711551
914541021355846
103842834142057
111251811766379
12520925466889
1321b4baa81461
14d3dcbdba321
1569e6324d88c
hex37ebac39369

3842834142057 has 4 divisors (see below), whose sum is σ = 5123778856080. Its totient is φ = 2561889428036.

The previous prime is 3842834141983. The next prime is 3842834142097. The reversal of 3842834142057 is 7502414382483.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3842834142057 - 211 = 3842834140009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3842834142097) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 640472357007 + ... + 640472357012.

It is an arithmetic number, because the mean of its divisors is an integer number (1280944714020).

Almost surely, 23842834142057 is an apocalyptic number.

It is an amenable number.

3842834142057 is a deficient number, since it is larger than the sum of its proper divisors (1280944714023).

3842834142057 is a wasteful number, since it uses less digits than its factorization.

3842834142057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1280944714022.

The product of its (nonzero) digits is 5160960, while the sum is 51.

The spelling of 3842834142057 in words is "three trillion, eight hundred forty-two billion, eight hundred thirty-four million, one hundred forty-two thousand, fifty-seven".

Divisors: 1 3 1280944714019 3842834142057