Base | Representation |
---|---|
bin | 10001100000010001111111… |
… | …11010000110110110001011 |
3 | 12001021212001022202020021111 |
4 | 20300020333322012312023 |
5 | 20021130240142310010 |
6 | 213511124144351151 |
7 | 11051665513613434 |
oct | 1060107772066613 |
9 | 161255038666244 |
10 | 38492569103755 |
11 | 112a067483a418 |
12 | 439814b6154b7 |
13 | 1862aab809a40 |
14 | 97109bda848b |
15 | 46b4302e058a |
hex | 23023fe86d8b |
38492569103755 has 16 divisors (see below), whose sum is σ = 51459561881280. Its totient is φ = 27445099667328.
The previous prime is 38492569103609. The next prime is 38492569103789. The reversal of 38492569103755 is 55730196529483.
38492569103755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 38492569103755 - 221 = 38492567006603 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10210228647 + ... + 10210232416.
It is an arithmetic number, because the mean of its divisors is an integer number (3216222617580).
It is a 1-persistent number, because it is pandigital, but 2⋅38492569103755 = 76985138207510 is not.
Almost surely, 238492569103755 is an apocalyptic number.
38492569103755 is a deficient number, since it is larger than the sum of its proper divisors (12966992777525).
38492569103755 is a wasteful number, since it uses less digits than its factorization.
38492569103755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20420461110.
The product of its (nonzero) digits is 244944000, while the sum is 67.
The spelling of 38492569103755 in words is "thirty-eight trillion, four hundred ninety-two billion, five hundred sixty-nine million, one hundred three thousand, seven hundred fifty-five".
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