Base | Representation |
---|---|
bin | 1110101001001101… |
… | …0100101110000011 |
3 | 101010221202010220121 |
4 | 3222103110232003 |
5 | 31022304343042 |
6 | 1450021321111 |
7 | 166261250260 |
oct | 35223245603 |
9 | 11127663817 |
10 | 3930934147 |
11 | 1737a01008 |
12 | 918566197 |
13 | 4a851c14a |
14 | 2940d6267 |
15 | 180181367 |
hex | ea4d4b83 |
3930934147 has 4 divisors (see below), whose sum is σ = 4492496176. Its totient is φ = 3369372120.
The previous prime is 3930934103. The next prime is 3930934169. The reversal of 3930934147 is 7414390393.
3930934147 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3930934147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3930934747) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280781004 + ... + 280781017.
It is an arithmetic number, because the mean of its divisors is an integer number (1123124044).
Almost surely, 23930934147 is an apocalyptic number.
3930934147 is a deficient number, since it is larger than the sum of its proper divisors (561562029).
3930934147 is an equidigital number, since it uses as much as digits as its factorization.
3930934147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 561562028.
The product of its (nonzero) digits is 244944, while the sum is 43.
The square root of 3930934147 is about 62697.1621925586. The cubic root of 3930934147 is about 1578.2116906961.
The spelling of 3930934147 in words is "three billion, nine hundred thirty million, nine hundred thirty-four thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •