Base | Representation |
---|---|
bin | 1011011100110101000… |
… | …01000101101011111011 |
3 | 1101121112010012210020001 |
4 | 11232122201011223323 |
5 | 22421223200423433 |
6 | 500424040213431 |
7 | 40265446062460 |
oct | 5563241055373 |
9 | 1347463183201 |
10 | 393434389243 |
11 | 141944501905 |
12 | 6430046a277 |
13 | 2b14032776c |
14 | 150841dd667 |
15 | a37a2d757d |
hex | 5b9a845afb |
393434389243 has 4 divisors (see below), whose sum is σ = 449639302000. Its totient is φ = 337229476488.
The previous prime is 393434389217. The next prime is 393434389259. The reversal of 393434389243 is 342983434393.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 393434389243 - 213 = 393434381051 is a prime.
It is a super-2 number, since 2×3934343892432 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (393434386243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28102456368 + ... + 28102456381.
It is an arithmetic number, because the mean of its divisors is an integer number (112409825500).
Almost surely, 2393434389243 is an apocalyptic number.
393434389243 is a deficient number, since it is larger than the sum of its proper divisors (56204912757).
393434389243 is an equidigital number, since it uses as much as digits as its factorization.
393434389243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56204912756.
The product of its digits is 20155392, while the sum is 55.
The spelling of 393434389243 in words is "three hundred ninety-three billion, four hundred thirty-four million, three hundred eighty-nine thousand, two hundred forty-three".
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