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3952834994833 = 10936264541237
BaseRepresentation
bin111001100001010111010…
…100110110001010010001
3111222212221212102012002221
4321201113110312022101
51004230401224313313
612223523552141041
7555403636036324
oct71412724661221
914885855365087
103952834994833
11129442a33915a
1253a104537781
1322899b4b955a
14d94653427bb
156cc50463c8d
hex39857536291

3952834994833 has 4 divisors (see below), whose sum is σ = 3989099536180. Its totient is φ = 3916570453488.

The previous prime is 3952834994827. The next prime is 3952834994837. The reversal of 3952834994833 is 3384994382593.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3365859898384 + 586975096449 = 1834628^2 + 766143^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3952834994833 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3952834994837) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18132270510 + ... + 18132270727.

It is an arithmetic number, because the mean of its divisors is an integer number (997274884045).

Almost surely, 23952834994833 is an apocalyptic number.

It is an amenable number.

3952834994833 is a deficient number, since it is larger than the sum of its proper divisors (36264541347).

3952834994833 is a wasteful number, since it uses less digits than its factorization.

3952834994833 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36264541346.

The product of its digits is 604661760, while the sum is 70.

The spelling of 3952834994833 in words is "three trillion, nine hundred fifty-two billion, eight hundred thirty-four million, nine hundred ninety-four thousand, eight hundred thirty-three".

Divisors: 1 109 36264541237 3952834994833