Base | Representation |
---|---|
bin | 111010000110111110110… |
… | …001001111101001000001 |
3 | 112010202012201201002220221 |
4 | 322012332301033221001 |
5 | 1010411111122320040 |
6 | 12254243510303041 |
7 | 561333562100161 |
oct | 72067661175101 |
9 | 15122181632827 |
10 | 3993225198145 |
11 | 12aa576580777 |
12 | 545ab7057a81 |
13 | 22c737360241 |
14 | db3b76845a1 |
15 | 6dd1632674a |
hex | 3a1bec4fa41 |
3993225198145 has 4 divisors (see below), whose sum is σ = 4791870237780. Its totient is φ = 3194580158512.
The previous prime is 3993225198047. The next prime is 3993225198199. The reversal of 3993225198145 is 5418915223993.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2700083235249 + 1293141962896 = 1643193^2 + 1137164^2 .
It is a cyclic number.
It is not a de Polignac number, because 3993225198145 - 231 = 3991077714497 is a prime.
It is a super-2 number, since 2×39932251981452 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 399322519810 + ... + 399322519819.
It is an arithmetic number, because the mean of its divisors is an integer number (1197967559445).
Almost surely, 23993225198145 is an apocalyptic number.
It is an amenable number.
3993225198145 is a deficient number, since it is larger than the sum of its proper divisors (798645039635).
3993225198145 is an equidigital number, since it uses as much as digits as its factorization.
3993225198145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 798645039634.
The product of its digits is 20995200, while the sum is 61.
The spelling of 3993225198145 in words is "three trillion, nine hundred ninety-three billion, two hundred twenty-five million, one hundred ninety-eight thousand, one hundred forty-five".
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