Base | Representation |
---|---|
bin | 101101011110010110111101… |
… | …0110111011111010110000001 |
3 | 1221110021022022000121112211202 |
4 | 1122330231322313133112001 |
5 | 404412021130104013213 |
6 | 3534415532404150545 |
7 | 150152543064403565 |
oct | 13274557267372601 |
9 | 1843238260545752 |
10 | 399996660610433 |
11 | 1064a66a4028907 |
12 | 38a42048398455 |
13 | 142266a57569b3 |
14 | 70abd27d376a5 |
15 | 3139c6ed99b58 |
hex | 16bcb7addf581 |
399996660610433 has 4 divisors (see below), whose sum is σ = 400435734882048. Its totient is φ = 399557586338820.
The previous prime is 399996660610423. The next prime is 399996660610447. The reversal of 399996660610433 is 334016066699993.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 399996660610433 - 28 = 399996660610177 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (399996660610403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219537134441 + ... + 219537136262.
It is an arithmetic number, because the mean of its divisors is an integer number (100108933720512).
Almost surely, 2399996660610433 is an apocalyptic number.
It is an amenable number.
399996660610433 is a deficient number, since it is larger than the sum of its proper divisors (439074271615).
399996660610433 is an equidigital number, since it uses as much as digits as its factorization.
399996660610433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 439074271614.
The product of its (nonzero) digits is 918330048, while the sum is 74.
The spelling of 399996660610433 in words is "three hundred ninety-nine trillion, nine hundred ninety-six billion, six hundred sixty million, six hundred ten thousand, four hundred thirty-three".
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