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399996660610433 = 911439074270703
BaseRepresentation
bin101101011110010110111101…
…0110111011111010110000001
31221110021022022000121112211202
41122330231322313133112001
5404412021130104013213
63534415532404150545
7150152543064403565
oct13274557267372601
91843238260545752
10399996660610433
111064a66a4028907
1238a42048398455
13142266a57569b3
1470abd27d376a5
153139c6ed99b58
hex16bcb7addf581

399996660610433 has 4 divisors (see below), whose sum is σ = 400435734882048. Its totient is φ = 399557586338820.

The previous prime is 399996660610423. The next prime is 399996660610447. The reversal of 399996660610433 is 334016066699993.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 399996660610433 - 28 = 399996660610177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (399996660610403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219537134441 + ... + 219537136262.

It is an arithmetic number, because the mean of its divisors is an integer number (100108933720512).

Almost surely, 2399996660610433 is an apocalyptic number.

It is an amenable number.

399996660610433 is a deficient number, since it is larger than the sum of its proper divisors (439074271615).

399996660610433 is an equidigital number, since it uses as much as digits as its factorization.

399996660610433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 439074271614.

The product of its (nonzero) digits is 918330048, while the sum is 74.

The spelling of 399996660610433 in words is "three hundred ninety-nine trillion, nine hundred ninety-six billion, six hundred sixty million, six hundred ten thousand, four hundred thirty-three".

Divisors: 1 911 439074270703 399996660610433