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4000000000035 = 351320512820513
BaseRepresentation
bin111010001101010010100…
…101000100000000100011
3112011101200212200200222110
4322031102211010000203
51011014000000000120
612301324042010403
7561663505003164
oct72152245040043
915141625620873
104000000000035
1113024327a16a6
12547287aa6a03
13230276ac8760
14db85b33d76b
156e0b0eaa2e0
hex3a352944023

4000000000035 has 16 divisors (see below), whose sum is σ = 6892307692704. Its totient is φ = 1969230769152.

The previous prime is 3999999999967. The next prime is 4000000000039. The reversal of 4000000000035 is 5300000000004.

4000000000035 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 4000000000035 - 210 = 3999999999011 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4000000000035.

It is not an unprimeable number, because it can be changed into a prime (4000000000039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10256410062 + ... + 10256410451.

It is an arithmetic number, because the mean of its divisors is an integer number (430769230794).

Almost surely, 24000000000035 is an apocalyptic number.

4000000000035 is a deficient number, since it is larger than the sum of its proper divisors (2892307692669).

4000000000035 is a wasteful number, since it uses less digits than its factorization.

4000000000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20512820534.

The product of its (nonzero) digits is 60, while the sum is 12.

Adding to 4000000000035 its reverse (5300000000004), we get a palindrome (9300000000039).

The spelling of 4000000000035 in words is "four trillion, thirty-five", and thus it is an aban number.

Divisors: 1 3 5 13 15 39 65 195 20512820513 61538461539 102564102565 266666666669 307692307695 800000000007 1333333333345 4000000000035