Base | Representation |
---|---|
bin | 111010001101010010110… |
… | …100010100100101110001 |
3 | 112011101201011012221001111 |
4 | 322031102310110211301 |
5 | 1011014002011000423 |
6 | 12301324303433321 |
7 | 561663554003212 |
oct | 72152264244561 |
9 | 15141634187044 |
10 | 4000004000113 |
11 | 1302434a83a50 |
12 | 5472892b5841 |
13 | 230277899374 |
14 | db85baa1409 |
15 | 6e0b14ea60d |
hex | 3a352d14971 |
4000004000113 has 8 divisors (see below), whose sum is σ = 4363686235296. Its totient is φ = 3636329349600.
The previous prime is 4000004000063. The next prime is 4000004000141. The reversal of 4000004000113 is 3110004000004.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4000004000113 - 233 = 3991414065521 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4000004000093 and 4000004000102.
It is not an unprimeable number, because it can be changed into a prime (4000004000143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 764068 + ... + 2929813.
It is an arithmetic number, because the mean of its divisors is an integer number (545460779412).
Almost surely, 24000004000113 is an apocalyptic number.
It is an amenable number.
4000004000113 is a deficient number, since it is larger than the sum of its proper divisors (363682235183).
4000004000113 is a wasteful number, since it uses less digits than its factorization.
4000004000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3792335.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 4000004000113 its reverse (3110004000004), we get a palindrome (7110008000117).
The spelling of 4000004000113 in words is "four trillion, four million, one hundred thirteen", and thus it is an aban number.
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