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4000004000113 = 11984433693881
BaseRepresentation
bin111010001101010010110…
…100010100100101110001
3112011101201011012221001111
4322031102310110211301
51011014002011000423
612301324303433321
7561663554003212
oct72152264244561
915141634187044
104000004000113
111302434a83a50
125472892b5841
13230277899374
14db85baa1409
156e0b14ea60d
hex3a352d14971

4000004000113 has 8 divisors (see below), whose sum is σ = 4363686235296. Its totient is φ = 3636329349600.

The previous prime is 4000004000063. The next prime is 4000004000141. The reversal of 4000004000113 is 3110004000004.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4000004000113 - 233 = 3991414065521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4000004000093 and 4000004000102.

It is not an unprimeable number, because it can be changed into a prime (4000004000143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 764068 + ... + 2929813.

It is an arithmetic number, because the mean of its divisors is an integer number (545460779412).

Almost surely, 24000004000113 is an apocalyptic number.

It is an amenable number.

4000004000113 is a deficient number, since it is larger than the sum of its proper divisors (363682235183).

4000004000113 is a wasteful number, since it uses less digits than its factorization.

4000004000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3792335.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 4000004000113 its reverse (3110004000004), we get a palindrome (7110008000117).

The spelling of 4000004000113 in words is "four trillion, four million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 11 98443 1082873 3693881 40632691 363636727283 4000004000113