Base | Representation |
---|---|
bin | 111010001101010100011… |
… | …000010011110010001011 |
3 | 112011101202222112120220220 |
4 | 322031110120103302023 |
5 | 1011014030213224321 |
6 | 12301331041321123 |
7 | 561664322541336 |
oct | 72152430236213 |
9 | 15141688476826 |
10 | 4000030211211 |
11 | 1302448856811 |
12 | 5472960361a3 |
13 | 2302801458a8 |
14 | db86136561d |
15 | 6e0b39769c6 |
hex | 3a354613c8b |
4000030211211 has 4 divisors (see below), whose sum is σ = 5333373614952. Its totient is φ = 2666686807472.
The previous prime is 4000030211201. The next prime is 4000030211297. The reversal of 4000030211211 is 1121120300004.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4000030211211 - 211 = 4000030209163 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4000030211201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 666671701866 + ... + 666671701871.
It is an arithmetic number, because the mean of its divisors is an integer number (1333343403738).
Almost surely, 24000030211211 is an apocalyptic number.
4000030211211 is a deficient number, since it is larger than the sum of its proper divisors (1333343403741).
4000030211211 is a wasteful number, since it uses less digits than its factorization.
4000030211211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1333343403740.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 4000030211211 its reverse (1121120300004), we get a palindrome (5121150511215).
The spelling of 4000030211211 in words is "four trillion, thirty million, two hundred eleven thousand, two hundred eleven".
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