400003021130033 has 4 divisors (see below), whose sum is σ = 400003269319680. Its totient is φ = 400002772940388.

The previous prime is 400003021130003. The next prime is 400003021130057. The reversal of 400003021130033 is 330031120300004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-400003021130033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 400003021129987 and 400003021130014.

It is not an unprimeable number, because it can be changed into a prime (400003021130003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121661393 + ... + 124905966.

It is an arithmetic number, because the mean of its divisors is an integer number (100000817329920).

Almost surely, 2^{400003021130033} is an apocalyptic number.

It is an amenable number.

400003021130033 is a deficient number, since it is larger than the sum of its proper divisors (248189647).

400003021130033 is a wasteful number, since it uses less digits than its factorization.

400003021130033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 248189646.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 400003021130033 its reverse (330031120300004), we get a palindrome (730034141430037).

The spelling of 400003021130033 in words is "four hundred trillion, three billion, twenty-one million, one hundred thirty thousand, thirty-three".