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400130044003 = 675972090209
BaseRepresentation
bin1011101001010011001…
…10111111000001100011
31102020210202021021211101
411310221212333001203
523023431242402003
6503452303255231
740623411154024
oct5645146770143
91366722237741
10400130044003
1114476aa84388
126566a8aa517
132b969570b61
141551b574c4b
15a61d03511d
hex5d299bf063

400130044003 has 4 divisors (see below), whose sum is σ = 406102134280. Its totient is φ = 394157953728.

The previous prime is 400130043997. The next prime is 400130044007. The reversal of 400130044003 is 300440031004.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 400130044003 - 237 = 262691090531 is a prime.

It is a super-2 number, since 2×4001300440032 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (400130044007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2986045038 + ... + 2986045171.

It is an arithmetic number, because the mean of its divisors is an integer number (101525533570).

Almost surely, 2400130044003 is an apocalyptic number.

400130044003 is a deficient number, since it is larger than the sum of its proper divisors (5972090277).

400130044003 is an equidigital number, since it uses as much as digits as its factorization.

400130044003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5972090276.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 400130044003 its reverse (300440031004), we get a palindrome (700570075007).

The spelling of 400130044003 in words is "four hundred billion, one hundred thirty million, forty-four thousand, three".

Divisors: 1 67 5972090209 400130044003