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400312112113 = 669159828443
BaseRepresentation
bin1011101001101000111…
…01100001001111110001
31102021021102212022022201
411310310131201033301
523024314400041423
6503522325503201
740631051544604
oct5646435411761
91367242768281
10400312112113
111448538298a1
12656bb871b01
132b9981ba174
141553780a33b
15a62deeb2ad
hex5d347613f1

400312112113 has 4 divisors (see below), whose sum is σ = 400371947248. Its totient is φ = 400252276980.

The previous prime is 400312112093. The next prime is 400312112131. The reversal of 400312112113 is 311211213004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 400312112113 - 213 = 400312103921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (400312112713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29907531 + ... + 29920912.

It is an arithmetic number, because the mean of its divisors is an integer number (100092986812).

Almost surely, 2400312112113 is an apocalyptic number.

It is an amenable number.

400312112113 is a deficient number, since it is larger than the sum of its proper divisors (59835135).

400312112113 is an equidigital number, since it uses as much as digits as its factorization.

400312112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59835134.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 400312112113 its reverse (311211213004), we get a palindrome (711523325117).

The spelling of 400312112113 in words is "four hundred billion, three hundred twelve million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 6691 59828443 400312112113